Question

Giải phương trình :

\(\sqrt{8x-4}-\sqrt{\frac{25x}{2}-\frac{25}{4}}+2\sqrt{\frac{2x-1}{9}}=\frac{1}{2}\)

Answer 1

ĐKXĐ: \(x\ge\frac{1}{2}\)

\(\Leftrightarrow2\sqrt{2x-1}-\frac{5}{2}\sqrt{2x-1}+\frac{2}{3}\sqrt{2x-1}=\frac{1}{2}\)

\(\Leftrightarrow\frac{1}{6}\sqrt{2x-1}=\frac{1}{2}\)

\(\Leftrightarrow\sqrt{2x-1}=3\)

\(\Leftrightarrow2x-1=9\Rightarrow x=5\)