Question

Giải phương trình sau

1) \(\dfrac{11x^2-5x+6}{x^2+5x+6}=x\)

2)\(\dfrac{x-1}{x^2-1}+\dfrac{2}{x^2-x+1}=\dfrac{2x+3}{x^3+1}\)

3)\(\dfrac{1-x}{x^2-3x+2}-\dfrac{x}{1-2x}=2\)

giúp tớ với

Answer 1

1,\(pt\Leftrightarrow11x^2-5x+6=x^3+5x^2+6x\)

\(\Leftrightarrow x^3-6x^2+11x-6=0\)

\(\Leftrightarrow\left(x-2\right)\left(x-3\right)\left(x-1\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=2\\x=3\\x=1\end{matrix}\right.\)(tm)

Answer 2

2,\(pt\Leftrightarrow\frac{1}{x+1}+\frac{2}{x^2-x+1}=\frac{2x+3}{x^3+1}\)

\(\Leftrightarrow\frac{x^2-x+1+2x+2}{x^3+1}=\frac{2x+3}{x^3+1}\)

\(\Rightarrow x^2-x=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=1\end{matrix}\right.\)

Answer 3

3,\(pt\Leftrightarrow\frac{1}{2-x}-\frac{x}{1-2x}=2\)

\(\Rightarrow1-2x-2x+x^2=4-10x+4x^2\)

\(\Leftrightarrow3x^2-6x+3=0\)

\(\Leftrightarrow x=1\)