ĐKXĐ: \(x\ne0\)
Đặt \(\frac{x^2+1}{x}=t\)
\(\Rightarrow t+\frac{1}{t}=\frac{5}{2}\Leftrightarrow2t^2-5t+2=0\)
\(\Rightarrow\left[{}\begin{matrix}t=2\\t=\frac{1}{2}\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}\frac{x^2+1}{x}=2\\\frac{x^2+1}{x}=\frac{1}{2}\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x^2-2x+1=0\\2x^2-x+2=0\left(vn\right)\end{matrix}\right.\) \(\Rightarrow x=1\)