`(-7x^2+4)/(x^3+1)=5/(x^2-x+1)-1/(x+1)` \(Đkxđ:x\ne-1\)
`⇔(-7x^2+4)/[(x+1)(x^2-x+1)]=5/(x^2-x+1)-1/(x+1)`
`⇔-7x^2+4=5(x+1)-x^2+x-1`
`⇔6x^2+6x=0`
`⇔6x(x+1)=0`
\(\Leftrightarrow\left[{}\begin{matrix}x=0\left(tm\right)\\x=-1\left(ktm\right)\end{matrix}\right.\)
giải phương trình sau :
a) 5-(x-6) = 4(3-2x) b) 2x(x+2)2-8x2 = 2(x-2)(x2+4)
c) 7-(2x+4) = -(x+4) d) (x+1)(2x-3) = (2x-1)(x+5
f) \(\frac{7x-1}{6}+2x=\frac{16-x}{5}\)
e) \(\frac{\left(2x+1\right)^2}{5}-\frac{\left(x-1\right)^2}{3}=\frac{7x^2-14x-5}{15}\)
giải pt
1,\(\frac{1}{x-1}+\frac{2x^2-5}{x^3-1}=\frac{4}{x^2+x+1}\)
2,\(\frac{x+4}{2x^2-5x+2}+\frac{x+1}{2x^2-7x+3}=\frac{2x+5}{2x^2-7x+3}\)
3,\(\frac{x+1}{x-1}-\frac{x-1}{x+1}=3x\left(1-\frac{x-1}{x+1}\right)\)
4,\(\frac{2x}{x-1}+\frac{4}{x^2+2x-3=}=\frac{2x-5}{x+3}\)
5,\(\frac{1}{x-1}-\frac{7}{x+2}=\frac{3}{x^2+x-2}\)
6,\(\frac{x+3}{x-4}+\frac{x-1}{x-2}=\frac{2}{6x-8-x^2}\)
7,\(\frac{1}{x-1}-\frac{7}{x+2}=\frac{3}{1-x^2}\)
1. giải phương trình
a, \(\frac{7x-3}{x-1}=\frac{2}{3}\)
b, \(\frac{2\left(3-7x\right)}{1+x}=\frac{1}{2}\)
c,\(\frac{5x-1}{3x+2}=\frac{5x-7}{3x-1}\)
d,\(\frac{4x+7}{x-1}=\frac{12x+5}{3x+4}\)
Bài 1: Giải các phương trình sau:
a) \(\frac{\left(2x+1\right)^2}{5}-\frac{\left(x-1\right)^2}{3}=\frac{7x^2-14x-5}{15}\)
b) \(\frac{7x-1}{6}+2x=\frac{16-x}{5}\)
Bài 2: Giải các phương trình sau:
a) \(x+\frac{2x+\frac{x-1}{5}}{3}=1-\frac{3x-\frac{1-2x}{3}}{5}\)
b) \(\frac{3x-1-\frac{x-1}{2}}{3}-\frac{2x+\frac{1-2x}{3}}{2}=\frac{\frac{3x-1}{2}-6}{5}\)
giải phương trình : \(\frac{1}{x^2+5x+6}+\frac{1}{x^2+7x+12}+\frac{1}{x^2+9x+20}=\frac{3}{40}\)
Bài 3: Giải các phương trình sau bằng cách đưa về dạng ax+b =0 :
a) \(\frac{3x-11}{11}-\frac{x}{3}=\frac{3x-5}{7}-\frac{5x-3}{9}\)
b) \(\frac{9x-0,7}{4}-\frac{5x-1,5}{7}=\frac{7x-1,1}{6}-\frac{5\left(0,4-2x\right)}{5}\)
c) \(\frac{5\left(x-1\right)+2}{6}-\frac{7x-1}{4}=\frac{2\left(2x-1\right)}{7}-5\)
d) \(14\frac{1}{2}-\frac{2\left(x+3\right)}{5}=\frac{3x}{2}-\frac{2\left(x-7\right)}{3}\)
1,Giải Pt
a,\(\frac{3x-7}{2}+\frac{x+1}{3}=-16\)
b,\(x-\frac{x+1}{3}=\frac{2x+1}{5}\)
c,\(\frac{7-3x}{12}+\frac{3}{4}=2\left(x-2\right)+\frac{5\left(5-2x\right)}{6}\)
e,\(\frac{3\left(x+3\right)}{4}+\frac{1}{2}=\frac{5x+9}{3}-\frac{7x-9}{4}\)
Giải các phương trình sau bằng cách đưa về dạng ax + b = 0:
\(a,\frac{\left(2x+1\right)^2}{5}-\frac{\left(x-1\right)^2}{3}=\frac{7x^2-14x-5}{15}\)
\(b,\frac{x+1}{3}+\frac{3\left(2x+1\right)}{4}=\frac{2x+3\left(x+1\right)}{6}+\frac{7+12x}{12}\)
Bài 1: Giải phương trình
a, \(\frac{x-1}{x+1}\)-\(\frac{x^2+x-2}{x+1}\)=\(\frac{x+1}{x-1}\)-x-2
b, (3,3-11x)(\(\frac{7x+2}{5}\)+\(\frac{2\left(1-3x\right)}{3}\))
