\(\frac{3x}{\sqrt{3x+10}}=\sqrt{3x+1}-1\)(đk: \(x\ge-\frac{1}{3}\))(1)
đặt \(\sqrt{3x+1}=a\ge0\)
khi đó:
(1) \(\Leftrightarrow\frac{a^2-1}{a+9}=a-1\)
\(\Leftrightarrow a^2-1=a^2+8a-9\)
\(\Leftrightarrow8a=8\Leftrightarrow a=1\left(tm\right)\)
\(\Leftrightarrow\sqrt{3x+1}=1\Leftrightarrow x=0\left(tm\right)\)
vậy x=0 là nghiệm của phương trình
* mk k chắc lắm đâu có j sai bạn sửa cho mk nhé
Giai phuong trinh: \(\sqrt{3x+x^2+\dfrac{9}{4}}+\sqrt{x^2+3x+1}=0\)
\(2\sqrt[3]{3x-2}+3\sqrt{6-5x}-8=0\)
Giai phuong trinh
Giai phuong trinh va he phuong trinh:
a) \(\sqrt{x^2+6}=x-2\sqrt{x^2-1}\)
b) \(x^2+3x+1=\left(x+3\right).\sqrt{x^2+1}\)
c) \(\left\{{}\begin{matrix}x^2+y^2=11\\x+xy+y=3+4\sqrt{2}\end{matrix}\right.\)
1,thu gon bieu thuc
a A=\(\dfrac{a\sqrt{a}-8+2a-4\sqrt{a}}{a-4}\)
b,B=\(\dfrac{12\sqrt{6}}{\sqrt{7+2\sqrt{6}-\sqrt{7-2\sqrt{6}}}}\)
c, C=\(\dfrac{\sqrt{c^2+2c+1}}{\left|c\right|-1}\)
2,giai cac phuong trinh
a,\(x^2-9\sqrt{x}+14=0\)
b, \(\sqrt{3x^2-18x+28}+\sqrt{4x^2-24x+45}=-5-x^2+6\)
GIUP MINH VOI MINH CAN GAP
Giai phuong trinh:
\(\sqrt[3]{x+3}-\sqrt[3]{6-x}=1\)
Tìm x
a) \(\sqrt{4x}+\sqrt{\frac{x}{4}}+\frac{1}{2}\sqrt{49x}=6\)
b)3x + \(\sqrt{3x-7}\)= 7
Giải phương trình
\(\sqrt{3x+8+6\sqrt{3x-1}}+\sqrt{3x+8-6\sqrt{3x-1}}\)=3x+4
Rút gọn :
\(P=\frac{5\sqrt{x}+3x-10}{\left(\sqrt{x+2}\right)\left(\sqrt{x-1}\right)}\)
Tìm ĐKXĐ:
a; \(\sqrt[4]{\frac{2}{-7+3x}}\)
b; \(\sqrt{x-1}+\frac{\sqrt[3]{x+1}}{\sqrt{5-x}}\)
c; \(\sqrt[8]{2x-1}-\sqrt[3]{3-5x}\)
d; \(\sqrt{\frac{3x-6-2x}{\sqrt[3]{1-x}}}\)
