Question

giải phương trình

\(\dfrac{x+1}{2009}\)+\(\dfrac{x+2}{2008}\)=\(\dfrac{x+2007}{3}\)+\(\dfrac{x+2006}{4}\)

Answer 1

\(\dfrac{x+1}{2009}+\dfrac{x+2}{2008}=\dfrac{x+2007}{3}+\dfrac{x+2006}{4}\)

\(\Leftrightarrow\dfrac{x+1}{2009}+1+\dfrac{x+2}{2008}+1=\dfrac{x+2007}{3}+1+\dfrac{x+2006}{4}+1\)

\(\Leftrightarrow\dfrac{x+2010}{2009}+\dfrac{x+2010}{2008}=\dfrac{x+2010}{3}+\dfrac{x+2010}{4}\)

\(\Rightarrow x+2010=0\)

\(\Rightarrow x=-2010\)

Vậy pt có nghiệm duy nhất \(x=-2010\)

Answer 2

giải phương trình

x^2+x-2=0

vậy kết quả bằng mấy vậy