Question

Giải phương trình:

\(\dfrac{1}{x-3}+2\) = \(\dfrac{x-5}{3-x}\)

Answer 1

ĐKXĐ : \(x\ne3\)

\(\dfrac{1}{x-3}+2=\dfrac{x-5}{3-x}\)

<=> \(\dfrac{1+2\left(x-3\right)}{x-3}=\dfrac{5-x}{x-3}\)

=> \(1+2x-6=5-x\)

=> \(3x=10\)

=> \(x=\dfrac{10}{3}\) ( Thỏa mãn ĐKXĐ )

Vậy ...

Answer 2

bài này dễ mà :(

Answer 3

<=> \(\dfrac{1}{x-3}+\dfrac{2\left(x-3\right)}{x-3}+\dfrac{x-5}{x-3}=0\)

ĐK: x \(\ne3\)

\(\dfrac{1+2x-6+x-5}{x-3}=0\)

\(3x-10=0\)

=> x=\(\dfrac{10}{3}\)