\(\left\{{}\begin{matrix}\left(m+1\right).\left(m-1\right)x-\left(m-1\right)y=\left(m+1\right)\left(m-1\right)\\\end{matrix}\right.\\ x-\left(m-1\right)y=2\)
Giải hệ pt và pt sau:
a.\(\left\{{}\begin{matrix}\left(2x-3\right)\cdot\left(2y+4\right)=4x\cdot\left(y-3\right)+54\\\left(x+1\right)\cdot\left(3y-3\right)=3y\left(x+1\right)-12\end{matrix}\right.\)
b.\(\left\{{}\begin{matrix}x+y-1=0\\x^2+xy+3=0\end{matrix}\right.\)
c.\(\left\{{}\begin{matrix}2x-3y=5\\x^2-y^2=40\end{matrix}\right.\)
d.\(\left\{{}\begin{matrix}3x+2y=36\\\left(x-2\right)\left(y-3\right)=18\end{matrix}\right.\)
e.\(\left\{{}\begin{matrix}2x+y=5m-1\\x-2y=2\end{matrix}\right.\) . Tìm m để hệ có nghiệm (x;y) t/m x\(^2\)-2y\(^2\)=1
f. \(\frac{t^2}{t-1}+t=\frac{2t^2+5t}{t+1}\)
g.\(\frac{x^2+2x-3}{x^2-9}+\frac{2x^2-2}{x^2-3x+2}=8\)
Giải hệ pt:
\(\left\{{}\begin{matrix}\left(x-1\right)\left(y-1\right)\left(x+y-2\right)=6\\x^2+y^2-2x-2y=3\end{matrix}\right.\)
Cho hệ pt \(\left\{{}\begin{matrix}\left|x\right|+y=-1\\x^2+y^2=m\end{matrix}\right.\) tìm m để hệ pt có nghiệm
Giải hệ pt:
\(\left\{{}\begin{matrix}x^2+1+xy+y^2-4y=0\\\left(x^2+1\right)\left(x+y-2\right)=y\end{matrix}\right.\)
Giải hệ pt:
\(\left\{{}\begin{matrix}x+y+1=3xy\\\left(\dfrac{x}{y+1}\right)^2+\left(\dfrac{y}{x+1}\right)^2=\dfrac{1}{2}\end{matrix}\right.\)
giải hệ pt:\(\left\{{}\begin{matrix}x^2-2y+x=5\\y\left(y+x+1\right)=72\end{matrix}\right.\)
1. Giải các hpt sau:
a, \(\left\{{}\begin{matrix}x-y=4\\3x+4y=19\end{matrix}\right.\) b, \(\left\{{}\begin{matrix}x-\sqrt{3y}=\sqrt{3}\\\sqrt{3x}+y=7\end{matrix}\right.\)
2. Giải các hpt sau:
a, \(\left\{{}\begin{matrix}2-\left(x-y\right)-3\left(x+y\right)=5\\3\left(x-y\right)+5\left(x+y\right)=-2\end{matrix}\right.\) b, \(\left\{{}\begin{matrix}\dfrac{2}{x-2}+\dfrac{2}{y-1}=2\\\dfrac{2}{x-2}-\dfrac{3}{y-1}=1\end{matrix}\right.\)
c, \(\left\{{}\begin{matrix}x+y=24\\\dfrac{x}{9}+\dfrac{y}{27}=2\dfrac{8}{9}\end{matrix}\right.\) d, \(\left\{{}\begin{matrix}\sqrt{x-1}-3\sqrt{y+2}=2\\2\sqrt{x-1}+5\sqrt{y+2=15}\end{matrix}\right.\)
3. Cho hpt \(\left\{{}\begin{matrix}\left(m+1\right)x-y=3\\mx+y=m\end{matrix}\right.\)
a, Giải hpt khi m=\(\sqrt{2}\)
b, tìm giá trị của m để hpt có nghiệm duy nhất thỏa mãn: x+y>0
Giải hệ pt
\(\left\{{}\begin{matrix}x^2+1+y\left(x+y\right)=4y\\\left(x^2+1\right)\left(x+y-2\right)=y\end{matrix}\right.\)
Giải hệ pt;
\(\left\{{}\begin{matrix}xy\left(x+y\right)=x^2-xy+y^2\\\dfrac{1}{x^3}+\dfrac{1}{y^3}=16\end{matrix}\right.\)
