Question

giải giúp câu 16 của bài 14 i

Answer 1

`16)(2sqrtx-4)/(3sqrtx-4)-(4+2sqrtx)/(sqrtx-2)+(x+13sqrtx-20)/(3x-10sqrtx+8)`
`=((2sqrtx-4)(sqrtx-2)-(4+2sqrtx)(3sqrtx-4)+x+13sqrtx-20)/((3sqrtx-4)(sqrtx-2)`
`=(2x-8sqrtx+8-6x-4sqrtx+16+x+13sqrtx-20)/((3sqrtx-4)(sqrtx-2)`
`=(-3x+sqrtx+4)/((3sqrtx-4)(sqrtx-2)`
`=(-(3sqrtx-4)(sqrtx+1))/((3sqrtx-4)(sqrtx-2)`
`=(-(sqrtx+1))/(sqrtx-2)`

Answer 2

thank

Answer 3

18: Ta có: \(\dfrac{\sqrt{x}\left(16-\sqrt{x}\right)}{x-4}+\dfrac{3+2\sqrt{x}}{2-\sqrt{x}}-\dfrac{2-3\sqrt{x}}{\sqrt{x}+2}\)

\(=\dfrac{16\sqrt{x}-x}{\left(\sqrt{x}-2\right)\left(\sqrt{x}+2\right)}-\dfrac{\left(3+2\sqrt{x}\right)\left(\sqrt{x}+2\right)}{\left(\sqrt{x}-2\right)\left(\sqrt{x}+2\right)}-\dfrac{\left(2-3\sqrt{x}\right)\left(\sqrt{x}-2\right)}{\left(\sqrt{x}+2\right)\left(\sqrt{x}-2\right)}\)

\(=\dfrac{16\sqrt{x}-x-3\sqrt{x}-6-2x-4\sqrt{x}-2\sqrt{x}+4+3x-6\sqrt{x}}{\left(\sqrt{x}+2\right)\left(\sqrt{x}-2\right)}\)

\(=\dfrac{3\sqrt{x}-2}{x-4}\)