\(\dfrac{1}{x}+\dfrac{1}{x+6}=\dfrac{1}{4}\)
\(\Leftrightarrow\dfrac{4\left(x+6\right)}{4x\left(x=6\right)}+\dfrac{4x}{4x\left(x+6\right)}=\dfrac{x\left(x+6\right)}{4x\left(x+6\right)}\)
\(\Leftrightarrow4\left(x+6\right)+4x=x\left(x+6\right)\)
⇔ -x2 - 2x + 24 = 0
=> Δ =(-2)2 -4 . (-1). 24
= 100
=> x1= 4
x2 = -6