\(\text{Đ}K:\text{ }x\ge\frac{1}{2}\)
\(1\Leftrightarrow2x+2\sqrt{x^2-2x+1}=2\Leftrightarrow x+\sqrt{\left(x-1\right)^2}=1\Leftrightarrow x+\left|x-1\right|=1\)
\(+,x\ge1\Rightarrow\left|x-1\right|=x-1\Rightarrow2x-1=1\Leftrightarrow x=1\left(tm\right)\)
\(+,x< 1\Rightarrow\left|x-1\right|=1-x\Rightarrow1=1\left(\text{đ}ung\right)\Rightarrow\frac{1}{2}\le\text{ }x< 1\)
\(Vaay:\frac{1}{2}\le x\le1\)