Question

Giải các phương trình sau:

c) \(\dfrac{{2\left( {x + 1} \right)}}{3} - \dfrac{1}{2} = \dfrac{{1 + 3x}}{4}\);

Answer 1

\(\dfrac{{2\left( {x + 1} \right)}}{3} - \dfrac{1}{2} = \dfrac{{1 + 3x}}{4}\)

\(\dfrac{{2x + 2}}{3} - \dfrac{1}{2} = \dfrac{{1 + 3x}}{4}\)

\(\dfrac{{\left( {2x + 2} \right).4}}{{3.4}} - \dfrac{{1.6}}{{2.6}} = \dfrac{{\left( {1 + 3x} \right).3}}{{4.3}}\)

\(\dfrac{{8x + 8}}{{12}} - \dfrac{6}{{12}} = \dfrac{{3 + 9x}}{{12}}\)

\(8x + 8 - 6 = 3 + 9x\)

\(8x - 9x = 3 - 8 + 6\)

\( - x = 1\)

\(x =  - 1\)

Vậy phương trình có nghiệm \(x =  - 1\).