thực hiện các phép biến đổi để đưa các phương trình đã cho về các phương trình tương đương có dạng ax+b=0 hoặc ax=-b,ta được:
a)5x-2/3=5-3x/2⇔2(5x-2)=3(5-3x)⇔10x-4=15-9x⇔10x+9x=15+4⇔19x=19⇔x=1
phương trình có 1 nghiệm x=1
1) \(\dfrac{5x-2}{3}\)= \(\dfrac{5-3x}{2}\)
2) \(\dfrac{x+4}{5}\) - x + 4 = \(\dfrac{x}{3}\) - \(\dfrac{x-2}{2}\)
3) \(\dfrac{10x+3}{12}\)= 1 + \(\dfrac{6+8x}{9}\)
4) \(\dfrac{x+1}{3}\)- \(\dfrac{x-2}{6}\) = \(\dfrac{2x-1}{2}\)
Giải các phương trình sau:
a, \(\dfrac{3\left(5x-2\right)}{4}-2=\dfrac{7x}{3}-5\left(x-7\right)\)
b, \(\dfrac{x+5}{2}+\dfrac{3-2x}{4}=x-\dfrac{7+x}{6}\)
c, \(\dfrac{x-3}{11}+\dfrac{x+1}{3}=\dfrac{x+7}{9}-1\)
d, \(\dfrac{3x-0,4}{2}+\dfrac{1,5-2x}{3}=\dfrac{x+0,5}{5}\)
bài 4 giải các phương trình sau
b,\(\dfrac{x+2}{3}-\dfrac{3}{4}=\dfrac{x-1}{3}\)
d,\(\dfrac{x-2}{4}+\dfrac{x+1}{6}=\dfrac{2x}{3}\)
f,\(\dfrac{x+2}{4}+\dfrac{2x-3}{3}=\dfrac{x-12}{6}\)
h,\(\dfrac{10x+3}{12}=1+\dfrac{6+8x}{9}\)
j,\(\dfrac{2x-1}{5}-\dfrac{x-2}{3}=\dfrac{x+7}{15}\)
m,\(\dfrac{2+x}{5}-0,5x=\dfrac{1-2x}{4}+0,25\)
Giải các phương trình sau :
a) \(\dfrac{5\left(x-1\right)+2}{6}-\dfrac{7x-1}{4}=\dfrac{2\left(2x+1\right)}{7}-5\)
b) \(\dfrac{3\left(x-3\right)}{4}+\dfrac{4x-10,5}{10}=\dfrac{3\left(x+1\right)}{5}+6\)
c) \(\dfrac{2\left(3x+1\right)+1}{4}-5=\dfrac{2\left(3x-1\right)}{5}-\dfrac{3x+2}{10}\)
d) \(\dfrac{x+1}{3}+\dfrac{3\left(2x+1\right)}{4}=\dfrac{2x+3\left(x+1\right)}{6}+\dfrac{7+12x}{12}\)
GIẢI CÁC PHƯƠNG TRÌNH
a) \(x-\dfrac{5x+2}{6}=\dfrac{7-3x}{4}\)
b) \(\dfrac{10x+3}{12}=1+\dfrac{6+8x}{9}\)
c) \(\dfrac{x}{3}-\dfrac{2x+1}{2}=\dfrac{x}{6}-6\)
d) \(\dfrac{2+x}{3}-\dfrac{1}{2}x=\dfrac{1-2x}{4}+\dfrac{1}{4}\)
GIẢI CÁC PHƯƠNG TRÌNH
a) \(x-\dfrac{5x+2}{6}=\dfrac{7-3x}{4}\)
b) \(\dfrac{10x+3}{12}=1+\dfrac{6+8x}{9}\)
c) \(\dfrac{x}{3}-\dfrac{2x+1}{2}=\dfrac{x}{6}x\)
d) \(\dfrac{2+x}{3}-\dfrac{1}{2}x=\dfrac{1-2x}{4}+\dfrac{1}{4}\)
a) \(\dfrac{x-3}{5}=6-\dfrac{1-2x}{3}\)
b) \(\dfrac{3x-2}{6}-5=\dfrac{3-2\left(x+7\right)}{4}\)
c) \(2\left(x+\dfrac{3}{5}\right)=5-\left(\dfrac{13}{5}+x\right)\)
d) \(\dfrac{7x}{8}-5\left(x-9\right)=\dfrac{20x+1,5}{6}\)
1,\(\dfrac{5\left(x-1\right)+2}{6}\)-\(\dfrac{7x-1}{4x}\)=\(\dfrac{2\left(2x+1\right)}{7}\)-5
2,\(\dfrac{3\left(x-3\right)}{4}\)+\(\dfrac{4x-10,5}{10}\)=\(\dfrac{3 \left(x+1\right)}{5}\)+6
3,\(\dfrac{2\left(3x+1\right)+1}{4}\)-5=\(\dfrac{2\left(3x-1\right)}{5}\)-\(\dfrac{3x+2}{10}\)
Diễn giải ra cho em với ạ!Em cảm ơn
bài 3giải các phương trình sau
b,\(\dfrac{2x}{3}=8\)
d,\(\dfrac{6}{5}x=-9\)
f,\(\dfrac{2-3x}{4}=\dfrac{4x-5}{5}\)
h,\(\dfrac{10-3x}{2}=\dfrac{6x+1}{3}\)
