Question

bài 4 giải các phương trình sau

b,\(\dfrac{x+2}{3}-\dfrac{3}{4}=\dfrac{x-1}{3}\)

d,\(\dfrac{x-2}{4}+\dfrac{x+1}{6}=\dfrac{2x}{3}\)

f,\(\dfrac{x+2}{4}+\dfrac{2x-3}{3}=\dfrac{x-12}{6}\)

h,\(\dfrac{10x+3}{12}=1+\dfrac{6+8x}{9}\)

j,\(\dfrac{2x-1}{5}-\dfrac{x-2}{3}=\dfrac{x+7}{15}\)

m,\(\dfrac{2+x}{5}-0,5x=\dfrac{1-2x}{4}+0,25\)

Answer 1

k,\(\dfrac{x}{3}-\dfrac{2x+1}{2}=\dfrac{x}{6}-x\)

giúp mk câu k nhé đề bài như trên

Answer 2

b: \(\Leftrightarrow4x+8-9=4x-4\)

=>-1=-4(loại)

d: \(\Leftrightarrow3\left(x-2\right)+2\left(x+1\right)=8x\)

=>8x=3x-6+2x+2=5x-4

=>3x=-4

=>x=-4/3

f: \(\Leftrightarrow3\left(x+2\right)+4\left(2x-3\right)=2\left(x-12\right)\)

=>3x+6+8x-12=2x-24

=>11x-6=2x-24

=>9x=-18

=>x=-2