Question

Gía trị của \(-\frac{32^{xy}}{16^{xy}}\) khi \(xy=2\)

Answer 1

\(=-\frac{2^{5xy}}{2^{4xy}}=-2^{xy}=-2^2=-4\)

Answer 2

\(-\frac{32^{xy}}{16^{xy}}=-\frac{32^2}{16^2}=-\left(\frac{32}{16}\right)^2=-\left(2\right)^2=-4\)

Answer 3

<=>-\(\frac{2^{5xy}}{2^{4xy}}\)=-\(2^{xy}=-2^2=-4\)