Question

\(\frac{5x}{2x+2}+1=\frac{-6}{x+1}\) giải hộ mình với

Answer 1

\(\frac{5x}{2\left(x+1\right)}+\frac{x+1}{x+1}=\frac{-6}{x+1}\)

\(\frac{5x}{2\left(x+1\right)}+\frac{2\left(x+1\right)}{2\left(x+1\right)}=\frac{-12}{2\left(x+1\right)}\)

5x+2x+2=-12

2x+5x=-2-12

7x=-14

x=\(\frac{-14}{7}\)

x=-2

Answer 2

\(\frac{5x}{2x+2}+1=-\frac{6}{x+1}\)

\(5x+2\left(x+1\right)=-12\)

\(5x+2x+2=-12\)

\(7x=-14\)

\(x=-2\)

Answer 3

\(\frac{5x}{2x+2}\)+1=\(\frac{-6}{x+1}\) (ĐKXĐ:x≠-1)

⇔\(\frac{5x}{2\left(x+1\right)}\)+\(\frac{2x+2}{2\left(x+1\right)}\)=\(\frac{-12}{2\left(x+1\right)}\)

⇒5x+2x+2=-12

⇔7x=-14

⇔x=-2 (TMĐKXĐ)

Vậy tập nghiệm của phương trình đã cho là:S={-2}