\(\frac{3x+2}{x-1}+\frac{2x-4}{x+2}=5\)
\(\Rightarrow\frac{\left(3x+2\right)\left(x+2\right)+\left(2x-4\right)\left(x-1\right)}{\left(x-1\right)\left(x+2\right)}=5\)
\(\Rightarrow\frac{3x^2+2x+6x+4+2x^2-4x-2x+4}{\left(x-1\right)\left(x+2\right)}=5\)
\(\Rightarrow\frac{5x^2+2x+8}{\left(x-1\right)\left(x+2\right)}=5\)
\(\Rightarrow5x^2+2x+8=5\left(x-1\right)\left(x+2\right)\)
\(\Rightarrow5x^2+2x+8=5x^2-5x+10x-10\)
\(\Rightarrow5x^2-5x^2+2x-5x=8-10\)
\(\Rightarrow-3x=-2\)
\(\Rightarrow x=\frac{2}{3}\)
Làm nhanh giúp mình nhé
