Question

\(\frac{2x-1}{3}=\frac{x+2}{5}+1\)

Answer 1

x =2

Answer 2

Ta có:\(\frac{2x-1}{3}=\frac{x+2}{5}+1\)

\(\frac{2x-1}{3}=\frac{x+7}{5}\)

\(\Rightarrow5\left(2x-1\right)=3\left(x+7\right)\)

\(\Rightarrow10x-5=3x+21\)

\(\Rightarrow10x-3x=21+5\)

\(\Rightarrow7x=26\)

\(\Rightarrow x=\frac{26}{7}\)

Answer 3

\(\frac{2x-1}{3}=\frac{x+2}{5}+1\)

=> \(\frac{5.\left(2x-1\right)}{15}=\frac{3.\left(x+2\right)}{15}+\frac{15}{15}\)

=> \(5.\left(2x-1\right)=3.\left(x+2\right)+15\)

=> \(10x-5=3x+6+15\)

=> \(10x-3x=5+6+15\)

=> \(7x=26\)

=> \(x=\frac{26}{7}\)