\(4Al+3O_2\underrightarrow{t^o}2Al_2O_3\)
\(4:3:2\left(mol\right)\)
\(0,2:0,15:0,1\left(mol\right)\)
\(n_{Al}=\dfrac{m}{M}=\dfrac{5,4}{27}=0,2\left(mol\right)\)
\(a,m_{Al_2O_3}=n.M=0,1.\left(27.2+16.3\right)=0,1.102=10,2\left(g\right)\)
\(b,V_{O_2}=n.24,79=0,15.24,79=3,71885\left(l\right)\)