\(n_S=\frac{5}{32}\left(mol\right);n_{O_2}=\frac{6,4}{32}=0,2\left(mol\right)\)
\(PTHH:S+O_2\underrightarrow{t^o}SO_2\)
(mol)___\(\frac{5}{32}\)________\(\frac{5}{32}\)__
Tỉ lệ: \(\frac{\frac{5}{32}}{1}< \frac{0,2}{1}\rightarrow O_2\) dư
\(m_{SO_2}=m=\frac{5}{32}.64=10\left(g\right)\)