\(\dfrac{x+3}{8}\) = \(\dfrac{2}{x-3}\)
⇔ (x+3)(x-3)=16
⇔ x2 -9 =16
⇔x2 = 25
⇔ x=5; x=-5
\(\dfrac{x+3}{8}=\dfrac{2}{x-3}\)
\(\Rightarrow\left(x+3\right)\left(x-3\right)=2.8\)
\(\Rightarrow x^2-9=16\)
\(\Rightarrow x^2=25\)
\(\Rightarrow x=\pm5\)
Vậy \(x=\pm5\)