Question

\(\dfrac{x+3}{2}-\dfrac{x-1}{3}=1+\dfrac{x+5}{6}\)

Answer 1

\(\dfrac{x+3}{2}-\dfrac{x-1}{3}=1+\dfrac{x+5}{6}\\ \Leftrightarrow\dfrac{3\left(x+3\right)}{6}-\dfrac{2\left(x-1\right)}{6}-\dfrac{6}{6}-\dfrac{x+5}{6}=0\\ \Leftrightarrow3x+9-2x+2-6-x-5=0\\ \Leftrightarrow0=0\left(luôn.đúng\right)\)

Vậy pt có vô số nghiệm

Answer 2

\(\Leftrightarrow\dfrac{3\left(x+3\right)-2\left(x-1\right)}{6}=\dfrac{6+\left(x+5\right)}{6}\)

\(\Leftrightarrow3\left(x+3\right)-2\left(x-1\right)=6+x+5\)

\(\Leftrightarrow3x+9-2x+2-11-x=0\)

\(\Leftrightarrow0=0\left(đúng\right)\)

Vậy \(x=R\)