a) 5(k+3x)(x+1)-4(1+2x)=80 x\(_0\)=2Tìm gt của kb) x+1=xc) x+2=0d) x+5=0e) (x+1)(2x-3)-3(x-2)=2(x-1)\(^2\)f) (x+1)(x\(^2\)-x+1)-2x=x(x-1)(x+1)g)\(\dfrac{x}{3}\)-\(\dfrac{5x}{6}\)-\(\dfrac{15x}{12}\)=\(\dfrac{x}{4}\)-5h) \(\dfrac{x-1}{2}\)-\(\dfrac{x+1}{15}\)-\(\dfrac{2x-13}{6}\)=0i) \(\dfrac{3\left(5x-2\right)}{4}\)-2=\(\dfrac{7x}{3}\)-5(x-7)
j) \(\dfrac{x-3}{11}\)+\(\dfrac{x+1}{3}\)=\(\dfrac{x+7}{9}\)-1k)\(\dfrac{3x-0,4}{2}\)+\(\dfrac{1,5-2x}{3}\)=\(\dfrac{x+0,5}{5}\)l) \(\dfrac{x-4}{5}\)+\(\dfrac{3x-2}{10}\)-x=\(\dfrac{2x-5}{3}\)-\(\dfrac{7x+2}{6}\)m) \(\dfrac{\left(2x-3\right)\left(2x+3\right)}{8}\)=\(\dfrac{\left(x-4\right)^{^2}}{6}\)+\(\dfrac{\left(x-2^{ }\right)^2}{3}\)n) \(\dfrac{7x^2-14x-5}{15}\)=\(\dfrac{\left(2x+1\right)^2}{5}\)-\(\dfrac{\left(x-1\right)^2}{3}\)o) \(\dfrac{\left(7x+1\right)\left(x-2\right)}{10}\)+\(\dfrac{2}{5}\)=\(\dfrac{\left(x-2^{ }\right)^2}{5}\)+\(\dfrac{\left(x-1\right)\left(x-2\right)}{10}\)
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