\(\dfrac{x^2-5}{x^3+1}+\dfrac{\left(x+1\right)\cdot\left(x+2\right)}{x^3+1}+\dfrac{x^2-x+x}{x^3+1}\)
=\(\dfrac{x^2-5+\left(x+1\right)\cdot\left(x+2\right)+x^2-x+1}{x^3+1}\)
=\(\dfrac{x^2-5+x^2+2\cdot x+x+2+x^2-x+1}{x^3+1}\)
=\(\dfrac{3\cdot x^2+2\cdot x-2}{x^3+1}\)
mình cx ko bt còn rút gọn nữa hay ko đâu ak