\(\dfrac{x-3}{12}=\dfrac{3}{x-3}\)
\(\Rightarrow\left(x-3\right)^2=36\)
\(\Rightarrow x-3=6\)
\(\Rightarrow x=9\)
\(\dfrac{x-3}{12}=\dfrac{3}{x-3}\)
⇒ ( x-3 ) . ( x-3 ) = 12.3
⇒ ( x - 3)2 = 36
⇒ ( x - 3 )2 = 62
⇒ x -3 = 6 hoặc x -3 = -6
* nếu x - 3 = 6
x=6+3
x=9
* nếu x - 3 = -6
x = -6 + 3
x= -3
Theo đề ta có:
\(\dfrac{x-3}{12}=\dfrac{3}{x-3}\)
=> (x-3) . (x-3) = 12.3
=> (x-3). (x-3) = 36
=> \(\left(x-3\right)^2\)= 36
=> \(\left(x-3\right)^2\)= \(6^2\)
=> \(\left[{}\begin{matrix}x-3=6\\x-3=-6\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=6+3\\x=-6+3\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=9\\x=-3\end{matrix}\right.\)