\(\dfrac{a\sqrt{b}+b\sqrt{a}}{\sqrt{ab}}:\dfrac{1}{\sqrt{a}-\sqrt{b}}\)
= \(\dfrac{\sqrt{a}.\sqrt{a}.\sqrt{b}+\sqrt{b}.\sqrt{b}.\sqrt{a}}{\sqrt{ab}}.\dfrac{\sqrt{a}-\sqrt{b}}{1}\)
= \(\dfrac{\sqrt{ab}\left(\sqrt{a}+\sqrt{b}\right)}{\sqrt{ab}}.\dfrac{\sqrt{a}-\sqrt{b}}{1}\)
= \(\left(\sqrt{a}+\sqrt{b}\right)\left(\sqrt{a}-\sqrt{b}\right)\)
= \(a-b\)
a,cmr \(\left(\sqrt{a}+\dfrac{b-\sqrt{ab}}{\sqrt{a}+\sqrt{b}}\right):\left(\dfrac{a}{\sqrt{ab}+b}+\dfrac{b}{\sqrt{ab}-a}-\dfrac{a+b}{\sqrt{ab}}\right)=\sqrt{b}-\sqrt{a}\)
b, A=\((\dfrac{a-\sqrt{a}}{\sqrt{a}-1}-\dfrac{\sqrt{a}+1}{a+\sqrt{a}}):\dfrac{\sqrt{a}+1}{a}\)
1.tìm đk của A để A có ngĩa
2.rút gọn A
3.tìm GTNN của A
Rút gọn các biểu thức sau
a,\(A=\left(\dfrac{1}{x-\sqrt{x}}+\dfrac{1}{\sqrt{x}-1}\right):\dfrac{\sqrt{x}+1}{x-2\sqrt{x}+1}\)
b,\(B=\dfrac{2\sqrt{x}-1}{\sqrt{x}+1}+\dfrac{3\sqrt{x}-1}{x-\sqrt{x}+1}-\dfrac{2x\sqrt{x}-2x+2\sqrt{x}-3}{x\sqrt{x}+1}\)
c,\(C=\left(1-\dfrac{x+3\sqrt{x}}{x-9}\right):\left(\dfrac{\sqrt{x}-3}{2-\sqrt{x}}+\dfrac{\sqrt{x}-2}{3+\sqrt{x}}-\dfrac{9-x}{x+\sqrt{x}-6}\right)\)
d,\(D=\left(\dfrac{\sqrt{x}}{3+\sqrt{x}}+\dfrac{x+9}{9-x}\right):\left(\dfrac{3\sqrt{x}+1}{x-3\sqrt{x}}-\dfrac{1}{\sqrt{x}}\right)\)
e,\(E=\dfrac{15\sqrt{x}-11}{x+2\sqrt{x}-3}+\dfrac{3\sqrt{x}-2}{1-\sqrt{x}}-\dfrac{2\sqrt{x}+3}{\sqrt{x}+3}\)
rút gọn:
A=\(x-4-\sqrt{16-8x^2+x^4}\left(x>4\right)\)
B=\(\dfrac{a+b-2\sqrt{ab}}{\sqrt{a}-\sqrt{b}}:\dfrac{1}{\sqrt{a}+\sqrt{b}}\left(a,b>0,a\ne b\right)\)
Cho A=\(\sqrt{a}+\dfrac{b-\sqrt{ab}}{\sqrt{a}+\sqrt{b}}\)
B=\(\dfrac{a}{\sqrt{ab}+b}+\dfrac{b}{\sqrt{ab}-a}-\dfrac{a+b}{\sqrt{ab}}\)
a) rút gọn A,B
b)tìm a,b để \(\dfrac{A}{B}>0\)
rút gọn:
\(\dfrac{\sqrt{a}+\sqrt{b}-1}{a+\sqrt{ab}}\)+\(\dfrac{\sqrt{a}-\sqrt{b}}{2\sqrt{ab}}\)
Thu gọn :
\(\left(\dfrac{a-4b}{\sqrt{a}+2\sqrt{b}}\right):\dfrac{\sqrt{ab}}{a\sqrt{b}+b\sqrt{a}}\)
\(P=\left(\dfrac{3x+3\sqrt{x}-3}{\left(\sqrt{x}+2\right)\left(\sqrt{x}-1\right)}+\dfrac{1}{\sqrt{x}+2}-\dfrac{\sqrt{x}-2}{\sqrt{x}-1}\right):\dfrac{\sqrt{x}}{\sqrt{x}+1}\)
a) Rút gọn P (x > o, x khác 1)
b) Tìm giá trị của x để P > 0
rút gọn, tính
C=(1-\(\dfrac{a+\sqrt{a}}{\sqrt{a}+1}\)) .(1+\(\dfrac{a-\sqrt{a}}{\sqrt{a}-1}\))
rút gọn:
A=\(\dfrac{\sqrt{a}+\sqrt{b}}{\sqrt{a}-\sqrt{b}}-\dfrac{\sqrt{a^3}-\sqrt{b^3}}{a-b}\left(a,b\ge0,a\ne b\right)\)
B=\(\left(\dfrac{\sqrt{x^3}+\sqrt{y^3}}{\sqrt{x}+\sqrt{y}}-\sqrt{xy}\right)\cdot\left(\dfrac{\sqrt{x}+\sqrt{y}}{x-y}\right)\left(x,y\ge0,x\ne y\right)\)
