\(\dfrac{3x+2}{x^2-2x+1}-\dfrac{6}{x^2-1}-\dfrac{3x-2}{x^2+2x+1}\)
\(=\dfrac{\left(3x+2\right)\left(x^2+2x+1\right)-6\left(x+1\right)\left(x-1\right)-\left(3x-2\right)\left(x^2-2x+1\right)}{\left(x+1\right)^2\left(x-1\right)^2}\)
\(=\dfrac{3x^3+6x^2+3x+2x^2+4x+2-6x^2+6-3x^3+6x^2-3x+2x^2-4x+2}{\left(x+1\right)^2\left(x-1\right)^2}\)
\(=\dfrac{10x^2+10}{\left(x+1\right)^2\left(x-1\right)^2}\)
\(=\dfrac{10\left(x^2+1\right)}{\left(x+1\right)^2\left(x-1\right)^2}\)
*hình như sai chỗ nào ấy chả biết*
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