1)Các phương trình có tương đương ko? Vì sao?
a)2x2 + 3x -1 =2x2 -1 và 3x =0
b)3x -1 + \(\dfrac{1}{x-2}=2x+1+\dfrac{1}{x-2}\) và \(3x-1=2x+16\)
2)Các bất phương trình có tương đương ko? Vì sao?
a)\(\dfrac{1}{2}x^2-x>1\) và \(x^2-2x>2\)
b)\(\dfrac{1-x}{3}< 1\) và \(x-1< 3\)
3)Giải các phương trình:
a)\(2x+5=20-3x\)
b)\(\left(2x-1\right)^2-\left(x+3\right)^2=0\)
c)\(\dfrac{5x-4}{2}=\dfrac{16x+1}{7}\)
d)\(\dfrac{2x+1}{6}-\dfrac{x-2}{4}=\dfrac{3-2x}{3}-x\)
e)\(\dfrac{2x}{x-1}+\dfrac{4}{x^2+2x-3}=\dfrac{2x-5}{x+3}\)
3.
a) \(2x+5=20-3x\)
\(\Leftrightarrow2x+3x=20-5\)
\(\Leftrightarrow5x=15\)
\(\Leftrightarrow x=3\)
Vậy \(S=\left\{3\right\}\)
b) \(\left(2x-1\right)^2-\left(x+3\right)^2=0\)
\(\Leftrightarrow\left[\left(2x-1\right)+\left(x+3\right)\right]\left[\left(2x-1\right)-\left(x+3\right)\right]=0\)
\(\Leftrightarrow\left(2x-1+x+3\right)\left(2x-1-x-3\right)=0\)
\(\Leftrightarrow\left(3x+2\right)\left(x-4\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}3x+2=0\\x-4=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{2}{3}\\x=4\end{matrix}\right.\)
Vậy \(S=\left\{-\dfrac{2}{3};4\right\}\)
c) \(\dfrac{5x-4}{2}=\dfrac{16x+1}{7}\)
\(\Leftrightarrow\left(5x-4\right)7=\left(16x+1\right)2\)
\(\Leftrightarrow35x-28=32x+2\)
\(\Leftrightarrow35x-32x=2+28\)
\(\Leftrightarrow2x=30\)
\(\Leftrightarrow x=15\)
Vậy \(S=\left\{15\right\}\)
d) \(\dfrac{2x+1}{6}-\dfrac{x-2}{4}=\dfrac{3-2x}{3}-x\)
\(\Rightarrow\left(2x+1\right)12-\left(x-2\right)18=\left(3-2x\right)24-72x\)
\(\Leftrightarrow24x+12-18x+36=72-48x-72x\)
\(\Leftrightarrow6x+48=72-120x\)
\(\Leftrightarrow6x+120x=72-48\)
\(\Leftrightarrow126x=24\)
\(\Leftrightarrow x=\dfrac{4}{21}\)
Vậy \(S=\left\{\dfrac{4}{21}\right\}\)
