Question

\(\dfrac{3x-2}{6}\) -5=\(\dfrac{3-2\left(x+7\right)}{4}\)

 

Answer 1

Ta có: \(\dfrac{3x-2}{6}-5=\dfrac{3-2\left(x+7\right)}{4}\)

\(\Leftrightarrow\dfrac{3x-2}{6}-\dfrac{30}{6}=\dfrac{3-2x-14}{4}\)

\(\Leftrightarrow\dfrac{3x-32}{6}=\dfrac{-2x-11}{4}\)

\(\Leftrightarrow4\left(3x-32\right)=6\left(-2x-11\right)\)

\(\Leftrightarrow12x-128=-12x-66\)

\(\Leftrightarrow12x-128+12x+66=0\)

\(\Leftrightarrow24x-62=0\)

\(\Leftrightarrow24x=62\)

hay \(x=\dfrac{31}{12}\)

Vậy: \(S=\left\{\dfrac{31}{12}\right\}\)