Ta có: \(\dfrac{3x-2}{6}-5=\dfrac{3-2\left(x+7\right)}{4}\)
<=> \(12\left(\dfrac{3x-2}{6}-5\right)=12.\dfrac{3-2\left(x+7\right)}{4}\)
<=> \(6x-4-60=9-6\left(x+7\right)\)
<=> \(6x-64=9-6x-42\)
<=> \(6x-64=-6x-33\)
<=> \(6x+6x-64+33=0\)
<=> 12x-31=0
vậy \(\dfrac{3x-2}{6}-5=\dfrac{3-2\left(x+7\right)}{4}\)
<=> 12x-31=0
Giải các phương trình sau :
a) \(\dfrac{5\left(x-1\right)+2}{6}-\dfrac{7x-1}{4}=\dfrac{2\left(2x+1\right)}{7}-5\)
b) \(\dfrac{3\left(x-3\right)}{4}+\dfrac{4x-10,5}{10}=\dfrac{3\left(x+1\right)}{5}+6\)
c) \(\dfrac{2\left(3x+1\right)+1}{4}-5=\dfrac{2\left(3x-1\right)}{5}-\dfrac{3x+2}{10}\)
d) \(\dfrac{x+1}{3}+\dfrac{3\left(2x+1\right)}{4}=\dfrac{2x+3\left(x+1\right)}{6}+\dfrac{7+12x}{12}\)
1,\(\dfrac{5\left(x-1\right)+2}{6}\)-\(\dfrac{7x-1}{4x}\)=\(\dfrac{2\left(2x+1\right)}{7}\)-5
2,\(\dfrac{3\left(x-3\right)}{4}\)+\(\dfrac{4x-10,5}{10}\)=\(\dfrac{3 \left(x+1\right)}{5}\)+6
3,\(\dfrac{2\left(3x+1\right)+1}{4}\)-5=\(\dfrac{2\left(3x-1\right)}{5}\)-\(\dfrac{3x+2}{10}\)
Diễn giải ra cho em với ạ!Em cảm ơn
Giải các phương trình sau:
a, \(\dfrac{3\left(5x-2\right)}{4}-2=\dfrac{7x}{3}-5\left(x-7\right)\)
b, \(\dfrac{x+5}{2}+\dfrac{3-2x}{4}=x-\dfrac{7+x}{6}\)
c, \(\dfrac{x-3}{11}+\dfrac{x+1}{3}=\dfrac{x+7}{9}-1\)
d, \(\dfrac{3x-0,4}{2}+\dfrac{1,5-2x}{3}=\dfrac{x+0,5}{5}\)
a) \(\dfrac{x-3}{5}=6-\dfrac{1-2x}{3}\)
b) \(\dfrac{3x-2}{6}-5=\dfrac{3-2\left(x+7\right)}{4}\)
c) \(2\left(x+\dfrac{3}{5}\right)=5-\left(\dfrac{13}{5}+x\right)\)
d) \(\dfrac{7x}{8}-5\left(x-9\right)=\dfrac{20x+1,5}{6}\)
\(\dfrac{3x-2}{6}\) -5=\(\dfrac{3-2\left(x+7\right)}{4}\)
Giải các phương trình :
a) \(3x-2=2x-3\)
b) \(3-4u+24+6u=u+27+3u\)
c) \(5-\left(x-6\right)=4\left(3-2x\right)\)
d) \(-6\left(1,5-2x\right)=3\left(-15+2x\right)\)
e) \(0,1-2\left(0,5t-0,1\right)=2\left(t-2,5\right)-0,7\)
f) \(\dfrac{3}{2}\left(x-\dfrac{5}{4}\right)-\dfrac{5}{8}=x\)
Giải các phương trình :
a) \(\dfrac{5x-2}{3}=\dfrac{5-3x}{2}\)
b) \(\dfrac{10x+3}{12}=1+\dfrac{6+8x}{9}\)
c) \(\dfrac{7x-1}{6}+2x=\dfrac{16-x}{5}\)
d) \(4\left(0,5-1,5x\right)=-\dfrac{5x-6}{3}\)
1, giải phương trình
a, 2( x - 0,5 ) + 3 = 0,25(4x - 1 )
b , 2.\(\left(x-\dfrac{1}{4}\right)-4=-6\left(-\dfrac{1}{3}x+0,5\right)+2\)
2, giải các phương trình
a, \(\dfrac{3x-2}{2}=\dfrac{1-2x}{3}\)
b, \(\dfrac{x-1}{3}+2=3-\dfrac{2x+5}{4}\)
c, \(\dfrac{x-1}{5}+x=\dfrac{x+1}{7}\)
d, 2(x - 2,5 ) = 0,25 +\(\dfrac{4x-3}{8}\)
các bạn ơi ! giúp mik với ! mai kiểm tra rồi
4,\(\dfrac{x+1}{3}\)+\(\dfrac{3\left(2x+1\right)}{4}\)=\(\dfrac{2x+3\left(x+1\right)}{6}\)+\(\dfrac{7+12x}{12}\)
5,\(\dfrac{2x}{3}\)+\(\dfrac{2x-1}{6}\)=4-\(\dfrac{x}{3}\)
6,\(\dfrac{x-1}{2}\)+\(\dfrac{x-1}{4}\)=1-\(\dfrac{2\left(x-1\right)}{3}\)
