Question

\(\dfrac{3.\sqrt{x}-6}{x-2\sqrt{x}}-\dfrac{1}{2-\sqrt{x}}+\dfrac{\sqrt{x}-3}{\sqrt{x}}\)

\(\left(\dfrac{x+4}{x-4}-\dfrac{\sqrt{x}}{\sqrt{x}+2}\right):\left(\dfrac{2\sqrt{x}}{x-2\sqrt{x}}-\dfrac{1}{\sqrt{x}}\right)\)

Rút gọn biểu thức

Answer 1

b: Ta có: \(\left(\dfrac{x+4}{x-4}-\dfrac{\sqrt{x}}{\sqrt{x}+2}\right):\left(\dfrac{2\sqrt{x}}{x-2\sqrt{x}}-\dfrac{1}{\sqrt{x}}\right)\)

\(=\dfrac{x+4-x+2\sqrt{x}}{\left(\sqrt{x}+2\right)\left(\sqrt{x}-2\right)}:\dfrac{2\sqrt{x}-\sqrt{x}+2}{\sqrt{x}\left(\sqrt{x}-2\right)}\)

\(=\dfrac{2\left(\sqrt{x}+2\right)}{\left(\sqrt{x}+2\right)}\cdot\dfrac{\sqrt{x}}{\sqrt{x}+2}\)

\(=\dfrac{2\sqrt{x}}{\sqrt{x}+2}\)