\(\dfrac{3}{7}x-1=\dfrac{1}{7}x\left(3x-7\right)\)
\(\Leftrightarrow3x-7=x\cdot\left(3x-7\right)\)
\(\Leftrightarrow3x-7-3x^2+7x=0\)
\(\Leftrightarrow-3x^2+10x-7=0\)
\(TC:a+b+c=\left(-3\right)+10-7=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=1\\x=\dfrac{-7}{-3}=\dfrac{7}{3}\end{matrix}\right.\)
\(S=\left\{1,\dfrac{7}{3}\right\}\)
\(\)
1,\(\dfrac{5\left(x-1\right)+2}{6}\)-\(\dfrac{7x-1}{4x}\)=\(\dfrac{2\left(2x+1\right)}{7}\)-5
2,\(\dfrac{3\left(x-3\right)}{4}\)+\(\dfrac{4x-10,5}{10}\)=\(\dfrac{3 \left(x+1\right)}{5}\)+6
3,\(\dfrac{2\left(3x+1\right)+1}{4}\)-5=\(\dfrac{2\left(3x-1\right)}{5}\)-\(\dfrac{3x+2}{10}\)
Diễn giải ra cho em với ạ!Em cảm ơn
Giải các phương trình sau :
a) \(\dfrac{5\left(x-1\right)+2}{6}-\dfrac{7x-1}{4}=\dfrac{2\left(2x+1\right)}{7}-5\)
b) \(\dfrac{3\left(x-3\right)}{4}+\dfrac{4x-10,5}{10}=\dfrac{3\left(x+1\right)}{5}+6\)
c) \(\dfrac{2\left(3x+1\right)+1}{4}-5=\dfrac{2\left(3x-1\right)}{5}-\dfrac{3x+2}{10}\)
d) \(\dfrac{x+1}{3}+\dfrac{3\left(2x+1\right)}{4}=\dfrac{2x+3\left(x+1\right)}{6}+\dfrac{7+12x}{12}\)
Giải các phương trình sau:
a, \(\dfrac{3\left(5x-2\right)}{4}-2=\dfrac{7x}{3}-5\left(x-7\right)\)
b, \(\dfrac{x+5}{2}+\dfrac{3-2x}{4}=x-\dfrac{7+x}{6}\)
c, \(\dfrac{x-3}{11}+\dfrac{x+1}{3}=\dfrac{x+7}{9}-1\)
d, \(\dfrac{3x-0,4}{2}+\dfrac{1,5-2x}{3}=\dfrac{x+0,5}{5}\)
b. \(14\dfrac{1}{2}-\dfrac{2\left(x+3\right)}{5}=\dfrac{3x}{2}-\dfrac{2\left(x-7\right)}{3}\)
giải phương trình:
a. ( 2x-1 )3 + 6(3x-1)2 = 2( x+1) 3 + 6(x+2)3
b.(x-2)2 + (3-2x)2- (4x-4) (x-5)= (x+3)2
c. x-3+ \(\dfrac{2\left(x-3\right)-1}{3}\)=\(\dfrac{3-x}{4}\)
d. \(\dfrac{\dfrac{x+4}{3}-1}{7}=\dfrac{\dfrac{2-x}{7}+x}{3}+x+1\)
GIẢI CÁC PHƯƠNG TRÌNH
a) \(x-\dfrac{5x+2}{6}=\dfrac{7-3x}{4}\)
b) \(\dfrac{10x+3}{12}=1+\dfrac{6+8x}{9}\)
c) \(\dfrac{x}{3}-\dfrac{2x+1}{2}=\dfrac{x}{6}x\)
d) \(\dfrac{2+x}{3}-\dfrac{1}{2}x=\dfrac{1-2x}{4}+\dfrac{1}{4}\)
GIẢI CÁC PHƯƠNG TRÌNH
a) \(x-\dfrac{5x+2}{6}=\dfrac{7-3x}{4}\)
b) \(\dfrac{10x+3}{12}=1+\dfrac{6+8x}{9}\)
c) \(\dfrac{x}{3}-\dfrac{2x+1}{2}=\dfrac{x}{6}-6\)
d) \(\dfrac{2+x}{3}-\dfrac{1}{2}x=\dfrac{1-2x}{4}+\dfrac{1}{4}\)
4,\(\dfrac{x+1}{3}\)+\(\dfrac{3\left(2x+1\right)}{4}\)=\(\dfrac{2x+3\left(x+1\right)}{6}\)+\(\dfrac{7+12x}{12}\)
5,\(\dfrac{2x}{3}\)+\(\dfrac{2x-1}{6}\)=4-\(\dfrac{x}{3}\)
6,\(\dfrac{x-1}{2}\)+\(\dfrac{x-1}{4}\)=1-\(\dfrac{2\left(x-1\right)}{3}\)
\(\dfrac{3x-2}{6}\) -5=\(\dfrac{3-2\left(x+7\right)}{4}\)
