\(=\dfrac{3+3^5+3^9}{\left(3+3^5+3^9\right)+\left(3^3+3^7+3^{11}\right)}=\dfrac{3+3^5+3^9}{\left(3+3^5+3^9\right)+3^2\left(3+3^5+3^9\right)}\)
\(=\dfrac{\left(3+3^5+3^9\right)}{\left(3+3^5+3^9\right)\left(1+3^2\right)}=\dfrac{1}{1+9}=\dfrac{1}{10}\)