Question

\(\dfrac{2x+3}{2x-1}=\dfrac{x-3}{x+5}\)

Answer 1

\(\Leftrightarrow\left(2x+3\right)\left(x+5\right)=\left(x-3\right)\left(2x-1\right)\)

\(\Leftrightarrow2x^2+10x+3x+15=2x^2-x-6x+3\)

=>13x+15=-7x+3

=>20x=-12

hay x=-3/5(nhận)

Answer 2

<=>(2x+3)(x+5)=(2x-1)(x-3)

<=>2x^2+10x+3x+15=2x^2-6x-x+3

<=>(2x^2-2x^2)+(10x+3x+6x+x)=3-15

<=>20x=-12

<=>x=-3/5