ĐK: \(x\ne2\)
\(\dfrac{2-3.x}{x-2}=1^2_5\\ \Leftrightarrow\dfrac{2-3.x}{x-2}=\dfrac{7}{5}\\ \Leftrightarrow5.\left(2-3x\right)=7.\left(x-2\right)\\ \Leftrightarrow10-15x=7x-14\\ \Leftrightarrow-15x-7x=-14-10\\ \Leftrightarrow-22x=-24\\ \Leftrightarrow x=\dfrac{12}{11}\)
=> x=12/11