cái này k khó nhá bạn, bạn không hiểu chỗ nào dzậy
\(\dfrac{1}{4}+\dfrac{1}{3}:2x=-5\)
\(\dfrac{1}{4}+\dfrac{1}{3}=\dfrac{7}{12}\)
\(2x=\dfrac{7}{12}:-5=\dfrac{7}{-60}\)
\(x=\dfrac{-7}{60}:2=\dfrac{-7}{120}\)
Mình nghĩ vậy!!!
cái này k khó nhá bạn, bạn không hiểu chỗ nào dzậy
\(\dfrac{1}{4}+\dfrac{1}{3}:2x=-5\)
\(\dfrac{1}{4}+\dfrac{1}{3}=\dfrac{7}{12}\)
\(2x=\dfrac{7}{12}:-5=\dfrac{7}{-60}\)
\(x=\dfrac{-7}{60}:2=\dfrac{-7}{120}\)
Mình nghĩ vậy!!!
tìm x , biết :
a, \(\dfrac{37-x}{2x+5}=\dfrac{4}{9}\)
b, \(\dfrac{x-2}{x-1}=\dfrac{x+4}{x+7}\)
c, \(\dfrac{x+3}{25}=\dfrac{9}{x+3}\)
d, \(\dfrac{x}{\dfrac{-2}{3}}=\dfrac{5}{-x}\)
e, \(\dfrac{2x-5}{\dfrac{3}{2}}=\dfrac{\dfrac{-27}{8}}{5-2x}\)
f, \(\dfrac{\dfrac{5}{9}}{\left(3x-1\right)^2}=\dfrac{1-2x}{\dfrac{25}{3}}\)
Tìm x,y,z trong dãy tỉ số bằng nhau
1)\(\dfrac{3x}{8}=\dfrac{3y}{64}=\dfrac{3z}{216}\)và \(2x^2+2y^2.z^2=1\)
2) \(\dfrac{2x+1}{5}=\dfrac{4y-5}{9}=\dfrac{2x+4y-4}{7x}\)
3) \(\dfrac{x^3+y^3}{6}=\dfrac{x^3-2y^3}{4}\)và x6 . y6 =14
4) \(\dfrac{x+4}{6}=\dfrac{3y-1}{8}=\dfrac{3y-x-5}{x}\)
5) \(\dfrac{3}{x-1}=\dfrac{4}{y-2}=\dfrac{5}{z-3}\)và x.y.z=192
6)\(\dfrac{x-y}{3}=\dfrac{x+y}{13}=\dfrac{x.y}{200}\)
7)\(\dfrac{x+1}{2}=\dfrac{y-1}{3}=\dfrac{z+2}{4}=\dfrac{x+y+z+2}{2x+5}\)
8) \(\dfrac{15}{x-9}=\dfrac{20}{y-12}=\dfrac{40}{z-24}\)và x.y = 1200
9)\(\dfrac{40}{x-30}=\dfrac{20}{y-15}=\dfrac{28}{z-21}\) và x.y.z = 22400
10)15x = -10y =6z và x.y.z = -30000
11) Cho\(\dfrac{x+1}{3}=\dfrac{y-2}{5}=\dfrac{2z+14}{9}\)và x+z=y
12) Cho \(\dfrac{x}{3}=\dfrac{y}{4}\)và \(\dfrac{y}{5}=\dfrac{z}{6}\).Tính M=\(\dfrac{2x+3y+4z}{3x+4y+5z}\)
Tìm x, biết rằng:
1) ( 2x + 1)3 = -0,001
2) ( 2x -3 )4 = ( 2x-3 )6
3) ( 2x+1 )5 = ( 2x+1)2010
4) \(\dfrac{8}{25}=\dfrac{2^x}{5^{x-1}}\)
5) 9x : 3x = 3
6) \(3^x+3^{x+3}=756\)
7) \(5^{x+1}+6.5^{x+1}=875\)
8) \(2^{x-1}.3^{y+1}=12^{x+9}\)
9) \(3^x=9^{y-1}\)
10) \(2^{x+1}.5^y=20^x\)
11) 15x : 3y = 75y
12) \(\dfrac{3}{5}:\dfrac{2x}{15}=\dfrac{1}{2}:\dfrac{4}{5}\)
13) \(\dfrac{x}{2}=\dfrac{y}{3}=\dfrac{z}{4}\) và xy + yz + zx = 104
a) \(\dfrac{a}{2}=\dfrac{b}{3};\dfrac{b}{4}=\dfrac{c}{5}\) và a+b+c=2 d) \(\dfrac{x+1}{3}=\dfrac{y-2}{4}=\dfrac{z-1}{13}\) và 2x-3y+z=42
b) 2a = 3b = 5c và a+b-c =3 i) x:y:z = 2:3:5 và x*y*z=810
c) \(\dfrac{x}{7}=\dfrac{y}{3}\) và x - 42 =y \(\dfrac{x}{2}=\dfrac{y}{3};\dfrac{y}{4}=\dfrac{z}{5}\) và x2 - y2 = -16
các bạn giúp mình với, mình k biết làm. help me!!!!!
\(\dfrac{1}{4}+\dfrac{1}{3}:2x=-5\)
Tìm x
a) |x|=\(\dfrac{1}{2}\)
b)|2x+\(\dfrac{1}{2}\)|=\(\dfrac{3}{4}\)
c)|2x+\(\dfrac{3}{4}\)|-\(\dfrac{-1}{2}\)= \(\dfrac{5}{2}\)
d)|2x+1|=x+1
e)|2x+1|+|4x+2|+|6x+5|=5
f)|x|≤ 3 (x∈Z)
h) |x+\(\dfrac{1}{2}\)| + | x + \(\dfrac{1}{3}\)| + | x+ \(\dfrac{1}{4}\)| = x
Các bạn ơi !!!! giúp mình nha mình cần gấp lắm!!! ai đúng mình sẽ tick cho nhé iu các bạn <3
Tìm x :
a) \(3^{x+1}+2x.3^x-18x-27=0\)
b) \(\dfrac{1}{2}\left|2x+5\right|-\dfrac{5}{4}\left|4x+10\right|+\dfrac{7}{3}\left|-20-8x\right|=\dfrac{1}{6}\)
a, 4(5x-3)-3(2x+1)=9
b, |x-9|=2x+5
c, \(\dfrac{2}{x-3}+\dfrac{3}{x+3}=\dfrac{3x+5}{x^2-9}\)
Bài 1:Tìm x,biết:
a.\(\dfrac{11}{12}\)-\(\left(\dfrac{2}{5}+x\right)\)=\(\dfrac{2}{3}\)
b.\(2\dfrac{3}{4}x=3\dfrac{1}{7}:\left(0,01\right)\)
c.2x . (x-\(\dfrac{1}{7}\)) = 0
d.3,8 : 2x = \(\dfrac{1}{4}:2\dfrac{2}{3}\)