Sửa đề
\(2x^2-5x+3=0\)
<=> \(\left(2x^2-2x\right)-\left(3x-3\right)\)
<=> \(2x\left(x-1\right)-3\left(x-1\right)=0\)
<=> \(\left(x-1\right)\left(2x-3\right)=0\)
=>\(\left[{}\begin{matrix}x-1=0\\2x-3=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=1\\x=\frac{3}{2}\end{matrix}\right.\)
2x2 + 5x - 3 = 0
\(\Leftrightarrow\) 2x2 - x + 6x - 3 = 0
\(\Leftrightarrow\) (2x2 - x) + (6x - 3) = 0
\(\Leftrightarrow\) x(2x - 1) + 3(2x - 1) = 0
\(\Leftrightarrow\) (2x - 1)(x + 3) = 0
\(\Leftrightarrow\) 2x - 1 = 0 hoặc x + 3 = 0
1) 2x - 1 = 0 \(\Leftrightarrow\) x = \(\frac{1}{2}\)
2) x + 3 = 0 \(\Leftrightarrow\) x = -3
Vậy............
