Question

dạng cơ bản:

(2x-3)(6-2x)=0

Answer 1

\(\left(2x-3\right)\left(6-2x\right)=0\)

\(\Leftrightarrow\left\{{}\begin{matrix}2x-3=0\\6-2x=0\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}x=\dfrac{3}{2}\\x=3\end{matrix}\right.\)

Vậy \(\left\{{}\begin{matrix}x=\dfrac{3}{2}\\x=3\end{matrix}\right.\)

Answer 2

(2x-3)(6-2x)=0

\(\Leftrightarrow\left[{}\begin{matrix}2x-3=0\\6-2x=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=3\end{matrix}\right.\)

Answer 3

\(\left(2x-3\right)\left(6-2x\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}2x-3=0\\6-2x=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=3\end{matrix}\right.\)

Vậy...

Answer 4

\(\left(2x-3\right)\left(6-2x\right)=0< =>\left[{}\begin{matrix}2x-3=0\\6-2x=0\end{matrix}\right.< =>\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=3\end{matrix}\right.\)

Answer 5

(2x-3)(6-2x)=0

=> 2x-3=0 hoặc 6-2x=0

*2x-3=0 *6-2x=0

2x=3 -2x=-6

x=\(\dfrac{3}{2}\) x=3

Vậy x=\(\dfrac{3}{2}\)hoặc x=3