Question

1, Thực hiện phép tính:

(-27).(-28)+(-27).128

2,Tìm số nguyên x biết

a,(x-3).(2x+6)=0

b,(2x-1) mũ 2=81

c,(2x+5) mũ 3=-27

d,(3x-2) mũ 3 -1=63

Answer 1

1) \(\left(-27\right).\left(-28+128\right)=-27.100=-2700\)

2a)\(\left(x-3\right)\left(2x+6\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x-3=0\\2x+6=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-3\end{matrix}\right.\)

b) \(\left(2x-1\right)^2=81\)

\(\sqrt{\left(2x-1\right)^2}=9\)

\(\left|2x-1\right|=9\)

\(\left[{}\begin{matrix}2x-1=9\\2x-1=-9\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=5\\x=-4\end{matrix}\right.\)

c) \(\left(2m+5\right)^3=-27\)

\(\sqrt[3]{\left(2m+5\right)^3}=-3\)

\(2m+5=-3\)

\(m=-4\)

d) \(\left(3x-2\right)^3=64\)

tương tự câu c