Question

d ) \(x^2-\frac{2}{3}x+\frac{1}{9}=0\)

Answer 1

d) \(x^2-\frac{2}{3}x+\frac{1}{9}=0\)

\(\Leftrightarrow\left(x-\frac{1}{3}\right)^2=0\)

\(\Leftrightarrow x-\frac{1}{3}=0\)

\(\Leftrightarrow x=\frac{1}{3}\)

Answer 2

d ) \(x^2-\frac{2}{3}x+\frac{1}{9}=0\)

     \(x^2-2.x.\frac{1}{3}+\left(\frac{1}{3}\right)^2=0\)

     \(\left(x-\frac{1}{3}\right)^2=0\)

      \(\left(x-\frac{1}{3}\right)=0\)

         \(x=0+\frac{1}{3}\)

          \(x=\frac{1}{3}\)