M(x)=x2+2x+1+|x-2|
=x2+x+x+1+|x-2|
=x(x+1)+(x+1)+|x-2|
=(x+1)(x+1)+|x-2|
=(x+1)2+|x-2|
(x+1)2+|x-2|=0
=>\(\left[{}\begin{matrix}\left(x+1\right)^2=0\\\left|x-2\right|=0\end{matrix}\right.\)
=>\(\left[{}\begin{matrix}x+1=0\\x-2=0\end{matrix}\right.\)
=>\(\left[{}\begin{matrix}x=-1\\x=2\end{matrix}\right.\)(vô lý)
=> Đa thức M(x)=x+2x+1+|x-2| vô nghiệm