Ta có:
\(a\left(b+c\right)-b\left(a+c\right)=ab+ac-ba-bc=ac-bc\left(1\right)\)
\(b\left(a-c\right)-a\left(b-c\right)=ba-bc-ab+ac=-bc+ac=ac-bc\left(2\right)\)Từ (1) và (2)\(\Rightarrow a\left(b+c\right)-b\left(a+c\right)=\)\(b\left(a-c\right)-a\left(b-c\right)\left(dpcm\right)\)