Có a // b
\(\Rightarrow\widehat{A_1}=\widehat{B_2}\)
\(\Rightarrow\dfrac{\widehat{A_1}}{2}=\dfrac{\widehat{B_2}}{2}\Rightarrowđpcm\)
Giải
\(a//b\)
Và \(\left\{{}\begin{matrix}c\cap a=\left\{A\right\}\\c\cap b=\left\{B\right\}\end{matrix}\right.\)
\(\Rightarrow\widehat{B_1}=\widehat{A_2}\)( sole trong )
Từ đó \(\Rightarrow\dfrac{\widehat{A_3}}{2}=\dfrac{\widehat{B_2}}{2}\), \(\dfrac{\widehat{B_1}}{2}=\dfrac{\widehat{A_4}}{2}\)