\(M=\frac{3}{8}+\frac{3}{15}+\frac{3}{7}\\ =\frac{3\cdot1}{8}+\frac{3\cdot1}{15}+\frac{3\cdot1}{7}\\ =3\cdot\left(\frac{1}{8}+\frac{1}{15}+\frac{1}{7}\right)\)
Mà \(3\cdot\left(\frac{1}{8}+\frac{1}{15}+\frac{1}{7}\right)>1\)
\(\Rightarrow M=\frac{3}{8}+\frac{3}{15}+\frac{3}{7}>1\)