\(31^{10}-1=\left(31^2\right)^5-1^5=\left(31^2-1\right)\left(31^8+5.31^6+...+5.31+1\right)\\ =960.\left(31^8+5.31^6+...+5.31+1\right)\)
ta có: \(\left\{{}\begin{matrix}960⋮6\\960⋮10\\960⋮5\end{matrix}\right.\)
đồng thời : \(UCLN\left(6,10,5\right)=1\)
do đó:
\(960⋮\left(5.6.10\right)\: hay\: 960⋮300\\ \Rightarrow960.\left(31^8+5.31^6+...+5.31+1\right)⋮300\\ hay\: 31^{10}-1⋮300\left(đpcm\right)\)