\(A=x^2+y^2+xy=\left(x+y\right)^2-2xy+xy\\ A=1-xy\)
Mà \(x+y=1\Leftrightarrow x=1-y\)
\(\Leftrightarrow A=1-\left(1-y\right)y=1-y+y^2=\left(y^2-y+\dfrac{1}{4}\right)+\dfrac{3}{4}\\ A=\left(y-\dfrac{1}{2}\right)^2+\dfrac{3}{4}\ge\dfrac{3}{4}\\ A_{min}=\dfrac{3}{4}\Leftrightarrow x=y=\dfrac{1}{2}\)