Áp dụng bđt Bunhiacopxki :
\(C=\frac{1}{10}\left(x^2+y^2\right)\left(1^1+3^2\right)\ge\frac{1}{10}\left(x+3y\right)^2\ge\frac{1}{10}\)
Dấu "=" \(\Leftrightarrow\left\{{}\begin{matrix}x=\frac{y}{3}\\x+3y=1\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=\frac{1}{10}\\y=\frac{3}{10}\end{matrix}\right.\)