Do x, y tỉ lệ thuận \(\Rightarrow\) đặt \(y=kx\Rightarrow\left\{{}\begin{matrix}y_1=k.x_1=6k\\y_2=k.x_2=-9k\end{matrix}\right.\)
\(y_1-y_2=10\Rightarrow6k-\left(-9k\right)=10\Rightarrow15k=10\Rightarrow k=\dfrac{2}{3}\)
\(\Rightarrow\left\{{}\begin{matrix}y_1=\dfrac{2}{3}.6=4\\y_2=\dfrac{2}{3}.\left(-9\right)=-6\end{matrix}\right.\)