Đặt \(\dfrac{x}{4}=\dfrac{y}{9}=k\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=4k\\y=9k\end{matrix}\right.\)
Ta có: xy=576
\(\Leftrightarrow36k^2=576\)
\(\Leftrightarrow k^2=16\)
Trường hợp 1: k=4
\(\Leftrightarrow\left\{{}\begin{matrix}x=4k=4\cdot4=16\\y=9k=9\cdot4=36\end{matrix}\right.\)
Trường hợp 2: k=-4
\(\Leftrightarrow\left\{{}\begin{matrix}x=4k=4\cdot\left(-4\right)=-16\\y=9k=9\cdot\left(-4\right)=-36\end{matrix}\right.\)
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