\(cosC=\dfrac{a^2+b^2-c^2}{2ab}=\dfrac{5}{7}\)
\(\Rightarrow sinC=\sqrt{1-cos^2C}=\dfrac{2\sqrt{6}}{7}\)
Áp dụng công thức trung tuyến:
\(AM=m_a=\dfrac{\sqrt{2\left(b^2+c^2\right)-a^2}}{2}=2\sqrt{7}\)
\(\Rightarrow R=\dfrac{AM}{2sinC}=\dfrac{7\sqrt{42}}{12}\)